anonymous
  • anonymous
Simplify Each Expression
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
http://waldenmath.zekemoore.com/wp-content/uploads/2011/01/20110114-Alg1-HW-Zero-and-Negative-Exponents.pdf
anonymous
  • anonymous
#'s 1-24
lalaly
  • lalaly
all of them:O

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

lalaly
  • lalaly
anything raised to the power 0 is 1
lalaly
  • lalaly
\[\large{x^{-m}=\frac{1}{x^m}}\]
anonymous
  • anonymous
Yea, i know that juss having a lil difficulty in 13-16
lalaly
  • lalaly
\[\frac{4}{n^2}=4n^{-2}\]
lalaly
  • lalaly
14) \[\frac{x^3}{2y^4}\]
lalaly
  • lalaly
\[15) \frac{a^0}{3b^{-3}}\]
anonymous
  • anonymous
ok so his is like solving for the exponent \[4n^x = 4/n^2 \]
lalaly
  • lalaly
\[16)3xy^{-5}\]
anonymous
  • anonymous
I think i get now :) Thanks guys
anonymous
  • anonymous
and then from there bring that exponent to the numerator to make it a negative and then since the bases are the same x = -2
lalaly
  • lalaly
:)
anonymous
  • anonymous
Thanks dada :)
anonymous
  • anonymous
:)

Looking for something else?

Not the answer you are looking for? Search for more explanations.