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anonymous
 4 years ago
A cannonball is fired into the air. It's height, h, in metres after t seconds is given by the relation:
h=4.6 (t7.5)^2+285
a) what is the maximum height reached by the cannon and what time is this reached.
b) what was the initial height of the cannon?
c) what is the height of the cannon after 10.5 seconds?
d) how long is the cannon in the air?
anonymous
 4 years ago
A cannonball is fired into the air. It's height, h, in metres after t seconds is given by the relation: h=4.6 (t7.5)^2+285 a) what is the maximum height reached by the cannon and what time is this reached. b) what was the initial height of the cannon? c) what is the height of the cannon after 10.5 seconds? d) how long is the cannon in the air?

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mathmate
 4 years ago
Best ResponseYou've already chosen the best response.0Do you just want just the answer or wnat to know how to find it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Can you show me how to find it please with the ans

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.2h = 4.6t²+69 t+26.25 the vertex of this function is the the time of maximum height time of maximum height = b/2a = 7.5 maximum height = 4.6(7.5)²+69(7.5)+26.25 = 285 meters 2) initial height (t = 0) = 26.25 meters 3) after 10.5 sec. (t = 10) = 243.6 meters 4) time in air (h = 0) t = 15.37

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y do u put h as zero?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can yu show us what yu plugged in for 4)

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.2this ball will reach a maximum heigh (h) then it returns back the same height (h) so it's total value = 0

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.2BTW..this will be from the position of projection , not the surface of the cannon

mathmate
 4 years ago
Best ResponseYou've already chosen the best response.0The answer to part a is already given in the way the formula is expressed: h=4.6(t7.5)^2+285 is in the vertex form. It shows that the vertex (highest or lowest point) is at the position (7.5,285), or a height of 285 after 7.5 seconds.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can yu put the equation where yu hav to isolste it so we kno wht to rite

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0or put in our calculator

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.2actually I can't find anything confusing here is the problem with expanding of the brackets ?!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no i jus dun understand how to solve 4)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0like how do u isolate "t" to find the time?

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.2did you understand why h = 0 ?!!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah we understand that, we just dont get how to put the "t" on one side of the equation, and the rest on the other side of the equation

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.2well, as h = 0 then h = 4.6 (t7.5)²+285 = 0 4.6 (t7.5)² = 285 [divide by 4.6] (t7.5)² = 61.95 [approx.] t7 = 8 or t7 = 8 [by taking +ve and ve square root] t = 15 or t = 1 [refused answer bec. t is never ve]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you :D charmi  u get it now? :P

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.2I'm glad you understood :)
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