anonymous
  • anonymous
What is the flux on an infinite line of charge?
Physics
schrodinger
  • schrodinger
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JamesJ
  • JamesJ
Flux is only measured and defined for a surface. If you insist on thinking of the line as a surface, then it is a surface with zero surface area and corresponding, the flux is also zero.
anonymous
  • anonymous
I know, I mean from a certain distance r on a cylinder... \[\Phi = \int\limits\limits\limits_{}^{} E dA = Q _{enc} / \epsilon _{0} \] \[\lambda = Q / l \] \[\Phi = E(2 \pi rl) = Q _{enc} / \epsilon _{0}\] \[\ E = \lambda l / (\ 2 \epsilon _{0} \pi rl)\]
JamesJ
  • JamesJ
right, and notice that \( \ell \) cancels. This is the calculation of the electric field, and you've got it.

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