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anonymous
 4 years ago
Find f^2(x), f^3(x), and f^n(x):
F(x)=x3
anonymous
 4 years ago
Find f^2(x), f^3(x), and f^n(x): F(x)=x3

This Question is Closed

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.4and the rest are the same

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm not sure about that: for the example problem: F(x)=x+1 F^2(x)=x+2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm studying iterated functions, if that helps at all

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1why is one f and the other F?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1so you have f^2 not f^(2) so f^2 means to square f

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ah, i didnt realize it was different. It is \[f ^{2}(x)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Which is what I put in the problem... lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok but then the example makes no sense according to that

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.4what are u studying about?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[f ^{2}(x) =f(fx))\] =\[f(x)+1\] =x+3 Studying iterated functions

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that example above is for f(x) = x+1

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.4oh ok so it would be\[f(x3)=(x3)3\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ah, weird...I guess it makes sense, but I dont know why

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i guess i just keep replacing x with x3?

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.4f(f(x)=f(x3) replace the x with x3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yep then how would i express that with n?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1so you are doing composition functions?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[f^3(x)=f \circ f \circ f (x)\] is this what is meant by your notation?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no, or at least we haven't talked about it at all

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it might be what is meant myinanaya

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm just putting in what is in the book

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1so no where in the book does it say how f^3 is defined?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for f(x) = x+1 \[f ^{3}(x)=f(f ^{2}(x))\] \[=f ^{2}(x)+1\] \[=(x+2)+1\] \[=x+3\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1lol lets assume what i thought is true okay?

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.4u dont have to assume lol it is true

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry I wasn't saying you were wrong earlier I was saying I wasn't really studying this

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.4it's okay i was wrong xD

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1\[f(x)=x3\] \[f^2=f \circ f(x)=f(x3)=(x3)3=x6\] \[f^3=f \circ f \circ f(x)=f(x6)=(x6)3=x9\] \[f^4=f \circ f \circ f \circ f(x)=f(x9)=(x9)3=x12\] so what is the pattern f=x3 f^2=x3(2) f^3=x3(3) f^4=x3(4) .... f^n=x3(n)=x3n

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1well i'm saying lalay f^2 can be read as f * f or f composed with f

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.1there might be other notations for all i know

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ah wow thank you so much! It makes a lot of sense now sorry the notation was confusing

lalaly
 4 years ago
Best ResponseYou've already chosen the best response.4yeah :) well found about something new:D
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