A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Three 1.0 nC charges are placed as shown in the figure. Each of these charges creates an electric field vector E at a point 3.0 cm in front of the middle charge.What are the three fields vector E1, vector E2, and vector E3 created by the three charges? Write your answer for each as a vector in component form.
anonymous
 4 years ago
Three 1.0 nC charges are placed as shown in the figure. Each of these charges creates an electric field vector E at a point 3.0 cm in front of the middle charge.What are the three fields vector E1, vector E2, and vector E3 created by the three charges? Write your answer for each as a vector in component form.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I mainly need help on starting it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry yes there is just hold on

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327883171291:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0q1,q2q3 all equal 1nC

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1so you need the field vector from each charge at that point on the right?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1327883385609:dwThe easiest one to find is the field due the the second charge\[\frac{1}{4\pi\epsilon_0}\frac{q}{r^2}\overrightarrow{r}=<0,\frac{1}{4\pi\epsilon_0}\frac{q}{r^2}>\]You can just plug the numbers in, and you know the angle will be 0 because the vector points in the +x direction. Got it so far?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I do understand that so far but it says to put it in vector component form. How would i do that? Like (Ex, Ey). I know Ey should be zero but how would you find Ex?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1this is component form:\[<0,\frac{1}{4\pi\epsilon_0}\frac{q}{r^2}>\]^^^ ^^^ Ex=0 Ey=that^

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1sorry Ex and Ey are backwards above...

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[<\frac{1}{4\pi\epsilon_0}\frac{q}{r^2},0>\] Ex^^ ^^Ey=0 I just noted that it says that the point is directly to the right of q2, so since the sine of 0=0 the ycomponent disappears.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now how do you find the components q1?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1let's put a grid on our point so we can do a little trigonometry:dw:1327884328041:dwThe next one I want to find is the vector due to q3. You will see why soon.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1notice all the geometry we can do here, and all the places this angle theta turns updw:1327884443364:dwwe can find r with the pythagorean theorem, and the angle with the inverse tangent.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[r=\sqrt{3^2+1}\]\[\theta=\tan^{1}(\frac13)\]so we have\[\overrightarrow{E_3}=\frac{1}{4\pi\epsilon_0}\frac{q_3}{r^2}\overrightarrow{r}=<\frac{1}{4\pi\epsilon_0}\frac{q_3}{r^2}\cos\theta,\frac{1}{4\pi\epsilon_0}\frac{q_3}{r^2}\sin\theta>\]so this can be solved quickly as well now

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1^I suppose you have to put the centimeters in terms of meters above actually

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[r=\sqrt{0.03^2+0.01^2}\]\[\theta=\tan^{1}(\frac13)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, i understand all of that so far.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1well if you have the radius and angle you can solve that guy, right? now E1 will be simple, because by symmetry it will have the same vector as E3, only the ycomponent will be negative\[\overrightarrow{E_1}=\frac{1}{4\pi\epsilon_0}\frac{q}{r^2}\overrightarrow{r}=<\frac{1}{4\pi\epsilon_0}\frac{q}{r^2}\cos\theta,\frac{1}{4\pi\epsilon_0}\frac{q}{r^2}\sin\theta>\]where theta is the angle we used earlier. Same r as well.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1dw:1327885322988:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks for helping this the set up. I'll let you know if it doesn't work on the homework. (it can be finicky sometimes)

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1please do, good luck!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For some reason it keeps saying I'm wrong for my q2 answer. I wrote that the answer was (1,0). I'm pretty sure it's right but just want to check with you (the answer is in kiloNewtons by the way).

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1let me bust out the calculator...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks for doing that :).

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1wait, the answer is in V/m or N/c or something, not just N that's force

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yep that worked. thanks, i now see what i did wrong.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1Have you tried the others yet? if not be careful of the units is all I can say...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, they all worked. Thank you very much

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1awesome! glad to help :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Your saving the world by helping one physics student at a time. lol
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.