anonymous
  • anonymous
The top of a building in Ottawa is 104m above the ground. Suppose an object was thrown upward with an initial velocity of 19.6m/s from this height. The approximate height of the object above the ground, h metres, t seconds after being thrown, would be given by the function: h=-4.9t^2+19.6t+104 a) what was the maximum height of the object,above the ground? b) after how many seconds did the object reach its maximum height? c) From the time the object was initially thrown, how much did it takes to reach the ground, to the nearest second?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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y2o2
  • y2o2
I think I've just solved this problem a second ago but with different words. :D
anonymous
  • anonymous
charmi, isnt this the same thing as the one before?
anonymous
  • anonymous
is it the same? idk it seems a bit different?

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y2o2
  • y2o2
just be informed that you won't use the velocity at all
y2o2
  • y2o2
just use Algebra and find the vertex of the function

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