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anonymous

  • 4 years ago

how do you turn -c^3d^-4 into a positive algebraic solution?

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  1. anonymous
    • 4 years ago
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    u change all the negative signs to positive

  2. anonymous
    • 4 years ago
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    i did that navi1996. and i put it over 1. but i still got it wrong.

  3. anonymous
    • 4 years ago
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    when you have negative exponents it is simplified, so you have to do 1/d^4 which is the same as d^-4, so the answer is -c^3/d^4

  4. anonymous
    • 4 years ago
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    it is not* simplified is what i meant

  5. anonymous
    • 4 years ago
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    you put the answer you have over one rright? if so, i did that and i still got it wrong.

  6. anonymous
    • 4 years ago
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    what do you mean put the answer over 1?

  7. anonymous
    • 4 years ago
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    under*...my bad.

  8. anonymous
    • 4 years ago
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    anything divided by 1 is itself.

  9. anonymous
    • 4 years ago
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    oh, you only put the d^4 over one because d^-4 is the same thing as 1/d^4. You dont do that with c^3 because its exponent is positive so you leave it on the top of the fraction. |dw:1327884383704:dw|

  10. anonymous
    • 4 years ago
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    still a little confused but its okay..i"ll figure it out. thank you!

  11. anonymous
    • 4 years ago
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    nevermind! i got it! thanks!

  12. anonymous
    • 4 years ago
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    you're welcome, is there a particular thing you are confused about? maybe I can help.

  13. anonymous
    • 4 years ago
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    good

  14. anonymous
    • 4 years ago
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    wouldn't the c be negative tho??

  15. anonymous
    • 4 years ago
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    nevermind.

  16. anonymous
    • 4 years ago
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    yes it is I forgot to put that in. good eye

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