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anonymous

  • 4 years ago

Argue that a triangle with sides x squared - 1; 2x; x squared + 1 is a right triangle.? PLEASE i need help.

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  1. anonymous
    • 4 years ago
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    umm which is the hypoteneuse

  2. anonymous
    • 4 years ago
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    it doesn't say

  3. anonymous
    • 4 years ago
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    well i think you use the pythagorean theorem.

  4. anonymous
    • 4 years ago
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    and ending result you would get 2x

  5. anonymous
    • 4 years ago
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    i think

  6. Directrix
    • 4 years ago
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    Use the converse of the Pythagorean Theorem. We do not know that the triangle is right; therefore, it has no hypotenuse yet. The square of one side of the triangle must be equal to the sum of the squares of the other two if the triangle is right. Square the 3 side lengths to determine if two of the squares sum to the third.

  7. anonymous
    • 4 years ago
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    ok thanks directrix ill try that.

  8. Directrix
    • 4 years ago
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    Find (x^2 -1) ^2, then (2x)^2, and then (x^2 +1)^2. See what you get. I will check.

  9. Directrix
    • 4 years ago
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    Should 2x be x^2 or perhaps (2x^2)^2? Just asking.

  10. anonymous
    • 4 years ago
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    :)

  11. anonymous
    • 4 years ago
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    no its 2x.

  12. Directrix
    • 4 years ago
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    Okay. What did you get for these three quantities? Find (x^2 -1) ^2, then (2x)^2, and then (x^2 +1)^2.

  13. anonymous
    • 4 years ago
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    x^4-1 and 4x^2 and x^4+1

  14. Directrix
    • 4 years ago
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    (x^2 -1) ^2 = x^4 - 2 x^2 +1 4x^2 Correct (x^2 +1)^2 = x^4 +2 x^2 + 1 Next Step: Will any two of these sum to the third. Note: Do not exponentiate over addition or subtraction. ( x + y) ^2 is NOT = x^2 + y^2. but does equal x^2 +2xy + y^2. You are thinking of (xy)^2 which DOES equal x^2 y^2

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