anonymous
  • anonymous
Argue that a triangle with sides x squared - 1; 2x; x squared + 1 is a right triangle.? PLEASE i need help.
Mathematics
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anonymous
  • anonymous
Argue that a triangle with sides x squared - 1; 2x; x squared + 1 is a right triangle.? PLEASE i need help.
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
umm which is the hypoteneuse
anonymous
  • anonymous
it doesn't say
anonymous
  • anonymous
well i think you use the pythagorean theorem.

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anonymous
  • anonymous
and ending result you would get 2x
anonymous
  • anonymous
i think
Directrix
  • Directrix
Use the converse of the Pythagorean Theorem. We do not know that the triangle is right; therefore, it has no hypotenuse yet. The square of one side of the triangle must be equal to the sum of the squares of the other two if the triangle is right. Square the 3 side lengths to determine if two of the squares sum to the third.
anonymous
  • anonymous
ok thanks directrix ill try that.
Directrix
  • Directrix
Find (x^2 -1) ^2, then (2x)^2, and then (x^2 +1)^2. See what you get. I will check.
Directrix
  • Directrix
Should 2x be x^2 or perhaps (2x^2)^2? Just asking.
anonymous
  • anonymous
:)
anonymous
  • anonymous
no its 2x.
Directrix
  • Directrix
Okay. What did you get for these three quantities? Find (x^2 -1) ^2, then (2x)^2, and then (x^2 +1)^2.
anonymous
  • anonymous
x^4-1 and 4x^2 and x^4+1
Directrix
  • Directrix
(x^2 -1) ^2 = x^4 - 2 x^2 +1 4x^2 Correct (x^2 +1)^2 = x^4 +2 x^2 + 1 Next Step: Will any two of these sum to the third. Note: Do not exponentiate over addition or subtraction. ( x + y) ^2 is NOT = x^2 + y^2. but does equal x^2 +2xy + y^2. You are thinking of (xy)^2 which DOES equal x^2 y^2

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