The top of a building in Ottawa is 104m above the ground. Suppose an object was thrown upward with an initial velocity of 19.6m/s from this height. The approximate height of the object above the ground, h metres, t seconds after being thrown, would be given by the function:
h=-4.9t^2+19.6t+104
a) what was the maximum height of the object,above the ground?
b) after how many seconds did the object reach its maximum height?
c) From the time the object was initially thrown, how much did it takes to reach the ground, to the nearest second?

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

a) 104 m

whats b

D: y is there 2 heights in the equation, theres like on (h) and then the max height (104)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.