anonymous
  • anonymous
Given a function and one of its zeros, find all the zeros of the function. h(x)=x^3-6x^2+10x-8 given zero: 4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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saifoo.khan
  • saifoo.khan
I hate when my words fly awaส็็็็็็็็็็็็็็็็็็็็็็็็็็
anonymous
  • anonymous
we can use synthetic division or just polynomial long division, personally as long as you are dividing by a linear factor, synthetic division is easier to me.
saifoo.khan
  • saifoo.khan
No help for badman.

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More answers

anonymous
  • anonymous
i like synthetic division as well
anonymous
  • anonymous
Synthethic division, divide the equation by (x - 4) and you get a quadratic equation. Solve that.
anonymous
  • anonymous
|dw:1327885683777:dw|
anonymous
  • anonymous
what this means is x^2 - 2x + 2
anonymous
  • anonymous
okay..and u just solve tht quadratic equation and then u get (x-2) sooo
anonymous
  • anonymous
It doesnt factor
anonymous
  • anonymous
oh..srrry..so basically u gotta complete the square?
anonymous
  • anonymous
or is tht the answer..im still confused
anonymous
  • anonymous
thats the answer. x^2 - 2x + 2 is one zero, and the other zero is already given
anonymous
  • anonymous
oh..okay so if it were factorable..tht wooda been the answer?
saifoo.khan
  • saifoo.khan
http://www.google.com.pk/search?ix=hca&sourceid=chrome&ie=UTF-8&q=synthetic+divison+khan+academy#q=synthetic+division+khan+academy&hl=en&safe=off&prmd=imvns&source=lnms&tbm=vid&ei=3-4lT8S0MIWAOtzI_b0I&sa=X&oi=mode_link&ct=mode&cd=3&ved=0CA8Q_AUoAg&bav=on.2,or.r_gc.r_pw.,cf.osb&fp=e721c247f98a2881&biw=1280&bih=699&ix=hca
anonymous
  • anonymous
kay..ima leave just as promised
anonymous
  • anonymous
it it was factorable you wouldve factored it and that wouldve been your answer
anonymous
  • anonymous
kay..thanks :D
anonymous
  • anonymous
welcome
saifoo.khan
  • saifoo.khan
badman?
anonymous
  • anonymous
saying my farewells
saifoo.khan
  • saifoo.khan
try out the khan-academy vids, it will help u out.
anonymous
  • anonymous
haha..sure, jus for u, mann..u always find sumthng to make u stand out :P
saifoo.khan
  • saifoo.khan
;)
anonymous
  • anonymous
kay..bye

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