anonymous
  • anonymous
A car traveling along the highway passes a point at 20 m/s. After 20 s, a police car passes the same point traveling at 30 m/s. how far down the road, and in what time will the police reach the first car?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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TuringTest
  • TuringTest
20 seconds after the first car passes the point (let's call it point x=0) we know the car is\[ vt=20(20)=400\] meters ahead. The position of the car after that time is then given by\[x_C=400+20t\]and the position of the police car is\[x_P=30t\]we can now represent mathematically the distance between the cars, then set it to zero and solve for t.
anonymous
  • anonymous
so are we gonna put it as: 30t = 400 + 20t
anonymous
  • anonymous
so t = 40s ?

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TuringTest
  • TuringTest
yep, that's what I got
anonymous
  • anonymous
and then from there we can find distance right? using any equation with distance
TuringTest
  • TuringTest
right
anonymous
  • anonymous
which velocity do i use to solve for distance ?
anonymous
  • anonymous
i got the distance as 1000m :O
TuringTest
  • TuringTest
it doesn't matter the velocity as long as you use one equation or the other, because at time t=40 our math says they should be equal\[400+20t=400+20(40)=400+800=1200m\]\[30t=30(40)=1200m\]
anonymous
  • anonymous
So the whole point is that you're not always using the kinematics equations you can use algebra to solve
TuringTest
  • TuringTest
Sure, why not? If you can solve it, do so in whatever way seems simplest. That keeps down typos. Don't get me wrong, you have to use the kinematic equations, but do so flexibly. They are to be changed and combined at will!
TuringTest
  • TuringTest
I meant you have to *learn the kinematic eqn..
TuringTest
  • TuringTest
but still\[x(t)=x_i+vt\]is a kinematic eqn, just a very simple one...
anonymous
  • anonymous
can you show me quickly how to solve using a kinematic equation :O
TuringTest
  • TuringTest
that is the kinematic above we used it, let xc be the car and xp be the police\[x_C(t)=x_i+vt=400+20t\]\[x_P(t)=x_i+vt=0+30t=30t\]or if you want to be thorough you can derive the formula from a more standard kinematic just by noting that the acceleration is zero\[x=x_i+v_it+\frac12at^2=x_i+v_it+\frac12(0)t=x_i+vt\]but that really seems like overkill
anonymous
  • anonymous
so we can assume that the acceleration is 0m/s^2
TuringTest
  • TuringTest
Well, there is no acceleration given, and I don't think we can solve it if there is one, so I'm gonna say 'yes' on that.
anonymous
  • anonymous
can you check out the other one i posted please. It has something to do with mass

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