solve the differential equation y''+y'-3y=0.

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solve the differential equation y''+y'-3y=0.

Mathematics
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\[r^2+r-3=0 => r=\frac{-1 \pm \sqrt{1 - 4(-3)}}{2}=\frac{-1 \pm \sqrt{13}}{2}\] this implies \[y=c_1 e^{\frac{-1+ \sqrt{13}}{2}}+c_2e^\frac{-1 - \sqrt{13}}{2}\]
oops missing something
yeah, its sqrty

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\[y=c_1 e^{\frac{-1+ \sqrt{13}}{2}x}+c_2e^{\frac{-1 - \sqrt{13}}{2}x}\]
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