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anonymous
 4 years ago
SOMEONE PLEASE HELP ME OUT WITH DOUBLE ANGLES !
anonymous
 4 years ago
SOMEONE PLEASE HELP ME OUT WITH DOUBLE ANGLES !

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Evaluate the expression using an appropriate double angle formula. 6tan(75) / 1tan^2(75)

precal
 4 years ago
Best ResponseYou've already chosen the best response.0can you use a calculator or not?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have to show the working

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0please could you show me how to do it ?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[\tan 2A=\frac{2\tan A}{1\tan ^{2}A}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{6\tan 75}{1\tan ^{2}75}=\frac{(3)2\tan 75}{1\tan ^{2}75}=3\tan 2A\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[2A=150, \tan(150)=\frac{\sqrt{3}}{3}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[3\tan 2A=3(\frac{\sqrt{3}}{3} )= \sqrt{3}\]
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