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anonymous
 4 years ago
(cos^4x−sin^4x)/(1−tan^4x)=cos^4x
trig identity?
anonymous
 4 years ago
(cos^4x−sin^4x)/(1−tan^4x)=cos^4x trig identity?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(\cos^4x−\sin^4x)/(1−\tan^4x)=\cos^4x\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how do you prove this? :/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i would start by factoring the numerator, and then see that one of the factors is 1. that should make the rest easier

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2you can factor Mr. Denominator as well

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i've tried that. i've went \[(\cos^2x+\sin^2x)(\cos^2x\sin^2x)/(1(\sin^4x/\cos^4x))\]

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1you don't need to get it all into sin and cos

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2cos^2(x)sin^2(x)=cos(2x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmm.. when i try, numerator part and denominator part keep gets messed up :/

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2\[\frac{\cos(2x)}{1\frac{\sin^4(x)}{\cos^4(x)}} \cdot \frac{\cos^4(x)}{\cos^4(x)}\] \[\frac{\cos^4(x) \cos(2x)}{\cos^4(x)\sin^4(x)}=\frac{\cos^4(x)\cos(2x)}{\cos(2x)}=\cos^4(x)\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2since we already showed \[\cos^4(x)\sin^4(x)=\cos(2x) \] earlier

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yup i've tried it out myself! thanks for the help.
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