A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
integrate sqrt((x^3 3)/x^11)
anonymous
 4 years ago
integrate sqrt((x^3 3)/x^11)

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327888347751:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0maybe we can take out that annoying \[x^{11}\] in the denominator and write is as \[\frac{1}{x^5}\sqrt{\frac{x^33}{x}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no that doesn't work. hmmm

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer in the back of the book is 2/27 (13/x^3)^(3/2)+C

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got the answer from wolfram, but not the "show steps" and the answer makes it look like a u  sub so maybe we can arrange it to be one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is supposed to be solved by u substitution

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i have another idea. write it as \[\frac{1}{x^4}\sqrt{\frac{x^33}{x^3}}\] and then make \[u=\frac{x^33}{x^3}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, thankyou so much

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yw let me know if you run in to any problems, but a miracle will occur when you find \[du\] it will be just what you want

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it gives me (9/x^7) as du.. :/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0check again, should be \[\frac{9}{x^4}\] as needed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i am gunna one more time.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{d}{dx}\frac{x^33}{x^3}=\frac{x^3\times 3x^23x^2\times (x^33)}{x^6}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0all the \[x^5\] terms go, you get \[\frac{9x^2}{x^6}=\frac{9}{x^4}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in fact you cannot get a power of 7 in the denominator, because \[(x^3)^2=x^6\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh shoot, i see my mistake, thankyou.. i was trying to do it with product rule

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0everyone thinks that is the easy way, but believe me it is not. even wolfram does it that way, but then you have to add the fractions an no one is good at that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah you are right, i will try not to use it, btw thankyou so much, ur a life saver

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{d}{dx}(\frac{x^33}{x^3})=\frac{d}{dx}(1\frac{3}{x^3})\] quotient rule not needed but good work (the credit for this little part goes to JamesJ) Great work on figuring out the substitution, satellite. You're awesome! :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\color{red}{\text{blush}}\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.