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anonymous

  • 4 years ago

Show an equation and a solution for the problem. Arnold needs a 25% solution of nitric acid. He has 20 milliliters (ml) of a 30% solution. How many ml of a 15% solution should he add to obtain the required 25% solution?

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  1. anonymous
    • 4 years ago
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    ready?

  2. anonymous
    • 4 years ago
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    yea lol

  3. anonymous
    • 4 years ago
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    ok he currently has 20 mg at 30% for a total of \[.3\times 20=6\] mg of acid. lets say he adds "x" mg or 15% solution. then the total amount of solution he will have is \[30+x\] and the "x" mg of 15% solution will contribute \[.15x\] acid. so he will have a total of \[6+.15x\] acid, and a total of \[30+x\] solution. now he wants that solution to be 255 acid, i.e. he want the total amount of acid to be \[.25(30+x)\]

  4. anonymous
    • 4 years ago
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    now that we have two expressions for the amount of acid he wants, we can set them equal and write \[6+.15x=.25(30+x)\] and solve for x

  5. anonymous
    • 4 years ago
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    if you need help solving let me know, but i would get rid of the decimals first by multiplying both sides by 100 to write \[600+15x=25(30+x)\]and work with whole numbers instead of decimals

  6. anonymous
    • 4 years ago
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    okay thank you i really needed that i understand now.

  7. anonymous
    • 4 years ago
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    and i see that i made a mistake, hold on a second

  8. anonymous
    • 4 years ago
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    oh alright.

  9. anonymous
    • 4 years ago
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    oh because i wasn't paying attention. he has 20 mg of 30% solution so the total amount is \[20+x\] not what i wrote. equation should be \[6+.15x=.25(20+x)\] i put a 30 instead of a 20

  10. anonymous
    • 4 years ago
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    sorry about that. solve \[600+15x=25(20+x)\]and you will get the answer. let me know if you have trouble but usually setting up the equation is the hard part, solving is the easy part

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