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anonymous
 4 years ago
Does anyone know how to do limits? I have a few homework questions I can't figure out.
anonymous
 4 years ago
Does anyone know how to do limits? I have a few homework questions I can't figure out.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I figured out the answer to the first question. I got the answer 6.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2\[\lim_{x \rightarrow 9}\frac{x9}{\sqrt{x}3}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2oh you did the first one ok

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The rest I am clueless on. I don't even know where to start.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2\[\lim_{x \rightarrow 0^+}\frac{1}{\sqrt[10](x)}\] first of all the limit is not 2

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2plug in even closer values to the right of 0 and you will see the number is getting really freaking huge so the limit is infinity also 1/(x^(1/10)) has a vertical asymptote at x=0 so we know it goes to infinity from the right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay great, I was on the right track because I kept getting a large number also.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2the 2nd one is ln(9) because i remember \[f'(9)=\frac{1}{ \ln(a)} \lim_{x \rightarrow 0}\frac{9^x9^0}{x0}=\ln(9)\] where \[f(x)=\frac{a^x}{\ln(a)} \] But i'm not sure if you know this yet

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2\[f'(x)=\frac{1}{ \ln(a)} \lim_{x \rightarrow 0}\frac{9^x9^0}{x0}=\ln(9)*\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no I have not learned that yet.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2ok then just plug in values really close to 0 on both sides and see if it gets closer to anything

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am getting close to 2. Am I way off? I am not sure if I am calculating correct.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.22.2 is a better number

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, I had 2.1972. We have only had whole number answers in our homework so far.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2well limits don't have to be whole numbers the numerical approach is okay but it only gives you approximations so if you want to put 2 i think that is close enough

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you so much! I think I kind of knew what I was doing on these problems but didn't trust myself. Can you go over the 4th question with me.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2I would make a piecewise function here

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2well you know what lets not do that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I don't know what a piecewise function is.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2lets just say this \[f(x)=\frac{(x8)(x+17)}{x8}=\frac{x^2+17x8x 136}{x8}=\frac{x^2+9x136}{x8}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2f is not defined at x=8 but tell me what happens as x>8 ?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2you know how i came up with my function?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So would I write down the function exists? I don't understand how to answer what they are asking. And yes please explain how you came up with the function.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2they want you to find a function f(x)=blah such that f(8) does not exist and as x>8, f>25

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2so I knew I wanted this from the f(8) doesn't exist part \[f(x)=\frac{something}{x8}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2but then i also since i wanted the limit to exist at x=8 so that means i wanted the x8 on bottom to cancel out with one on top \[f(x)=\frac{(x8)(something)}{x8}\] but we still need a little more something on top since we don't just want 1 because we want as x>8, f>25

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2so since the (x8)/(x8)>1 as x>8 we only need that something to go to 25 as x>8

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2if x>8 then x+17>25

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2\[f(x)=\frac{(x8)(x+17)}{x8}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I would have never figured that out. Thank you so much. And your explanation is awesome! You are one smart cookie! Too bad I couldn't have you tutor me for the res of the semester. It's very hard taking a math class online.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2i bet it is just keep coming back to openstudy and i or someone else will be here to help you out

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2people are addicted to this site

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well you are wonderful! You made my day! Thank you again!

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.2and thanks and welcome lol
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