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anonymous
 4 years ago
Four years ago, Jane was twice as old as Sam. Four years on from now, Sam will be 3/4 of Jane's age. How old is Jane now?
anonymous
 4 years ago
Four years ago, Jane was twice as old as Sam. Four years on from now, Sam will be 3/4 of Jane's age. How old is Jane now?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok now that i got that out of my system, lets see if we can do it.

Akshay_Budhkar
 4 years ago
Best ResponseYou've already chosen the best response.0LOL @satellite's attachement

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Let J denote Jane's current age, and S Sam's current age (J  4) = 2(S  4) (J + 4) = 3/4 (S + 4) Solve the system for J.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think I got it wrong... I think the second equation should be 3/4 (J + 4) = (S + 4)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0looks good to me. i was trying something that i thought might be simpler but it was more complicated

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i will write it anyway, and see if it makes sense

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yep I was definitely wrong in my first post. It should be J  4 = 2(s  4) 3/4 (J + 4) = S + 4 In which case you should get J=12, S=8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0as per marine, \[J4=2(S4)\] \[J4=2S8\] \[J=2S4\] is one equation. the next one is \[\frac{3}{4}(J+4)=S+4\] \[\frac{3}{4}J+3=S+4\] \[\frac{3}{4}J1=S\] now we can substitute \[J=\frac{3}{4}J1\] for S in the first equation and get \[J=2\times \frac{3}{4}(J1)4\] \[J=\frac{3}{2}J6\] \[6=\frac{1}{2}J\] \[J = 12\]
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