anonymous
  • anonymous
How do I find the zeroes for this problem? (x+5)^2/(x-3)^2+(x+5)^3/(x-3)^3 = 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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precal
  • precal
x=-5 I believe you are solving just the numerators
anonymous
  • anonymous
you have to combine the fractions and make it one. then find the x values that will make the numerator part 0.
anonymous
  • anonymous
-1 too, I think

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precal
  • precal
I did a quick graph and it shows -5 as a zero and -1
mathmate
  • mathmate
(x+5)^2/(x-3)^2+(x+5)^3/(x-3)^3 = 0 [ (x+5)^2(x-3) + (x+5)^3 ] /(x-3)^3 = 0 Factor the numerator to get (x+5)^2(2x+2)=0 => x=-5 (multiplicity 2) and x=-1 as precal got.
anonymous
  • anonymous
Thanks! I was so very close...

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