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anonymous

  • 4 years ago

If a ball is thrown straight up into the air with an initial velocity of 64 ft/sec, it's height in feet after t seconds is given by y=65t-16t^2. Find the average velocity for the time period beginning at t = 1 and lasting for .5, .1, and .01. I've done this about 10 times and consistently get -40 for the first which lasts .5 seconds which I'm told is incorrect. Help!

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  1. anonymous
    • 4 years ago
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    this is quite annoying, but you have to replace t by 1.5,1.1,1.01 and see what you get which one would you like to do?

  2. anonymous
    • 4 years ago
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    lets do 1.1 \[\frac{65\times 1.1-16(1.1)^2-49}{1.1-1}\] \[\frac{52.14-49}{.1}\] \[\frac{3.14}{.1}\] \[31.4\]

  3. anonymous
    • 4 years ago
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    others are similar, use a calculator

  4. anonymous
    • 4 years ago
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    or take this template, and replace 1.1 by your other two values (everywhere you see it) http://www.wolframalpha.com/input/?i=%2865%281.1%29-%2816%29%281.1%29^2-49%29%2F%281.1-1%29

  5. anonymous
    • 4 years ago
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    Thank you muchly!

  6. anonymous
    • 4 years ago
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    yw

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