At what point does the normal line to the curve y = x^2-3 at (1, -2) intersect the curve a second time?
The derivative is 2x so the slope at (1, -2) is 2 thus the equation of the tangent line is y+2 = 2 ( x-1) which I can graph both of, and am still not seeing where it crosses twice: http://www.wolframalpha.com/input/?i=y%2B2+%3D+2+%28+x-1%29+and+y+%3D+x%5E2-3

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Negative reciprocal! Geesh. That helps! Thanks!

Hehe, well, now you know :)

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