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anonymous
 4 years ago
The line containing the longer diagonal of a quadrilateral whose vertices are A (2, 2), B(2, 2), C(1, 1), and D(6, 4).
anonymous
 4 years ago
The line containing the longer diagonal of a quadrilateral whose vertices are A (2, 2), B(2, 2), C(1, 1), and D(6, 4).

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0calculate AC and BD using distance formula and the longer one will be the line containing the longer diagonal of the quadrilateral

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0AC = sqrt[(x2  x1)^2 + (y2  y1)^2]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0AC = sq.rt[(1  2)^2 + (1 2)^2] ac = sqrt[(1)^2 + (3)^2] AC = sqrt[1 + 9] ac = sqrt(10)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0similarly calculate BD

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0B(2, 2), D(6, 4). BD = sq.rt{[6  (2)]^2 + [4 (2)]^2} BD = sqrt[(6 + 2)^2 + (4 + 2)^2] BD = sqrt[(8)^2 + (6)^2] BD = sqrt(64 + 36) BD = sqrt(100) BD = 10 so BD is the longer one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you help me with another equation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Indicate the equation of the given line in standard form. The line containing the median of the trapezoid whose vertices are R(1, 5) , S(l, 8), T(7, 2), and U(2, 0). This is the question... and for the answer i got was: 13+xy=48? can you tell me where i went wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0We can first find the midpoints of the legs RU and ST using the Midpoint formula of a line segment. Then we find the distance between them by using the formula for Distance between Two Points.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327899962653:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0R(1, 5) , U(2, 0). midpoint of RU = X and its coordinates are 1 + 2 5 + 0 x =  and y =  so X = (1/2 , 5/2) 2 2 S(l, 8), T(7, 2), midpoint of ST = Y and its coordinates are 1 + 7 8 + (2) x =  and y =  so Y = (4, 3) 2 2 so we have to find the line passing through the points x (1/2, 5/2) and y(4, 3)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so we have to find the line passing through the points X= (1/2, 5/2) and Y=(4, 3) First we find the slope of the line y2  y1 3  5/2 1/2 m =  =  =  = 1/7 x2  x1 4  1/2 7/2 Now we use the Pointslope form and using one of the points, say Y, we find the equation of the line y  y1 = m(x  x1) y  3 = 1/7(x  4) y  3 = x/7  4/7 Now expressing it in standard form 3 + 4/7 = x/7  y x/7  y = 17/7 so eqn can be 1 17  x  y =   7 7 or x  7y = 17
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