## anonymous 4 years ago The slope of the secant line to the function f(x)=sqrt(x) between x=1 and x=16

$\frac{f(16)-f(1)}{16-1}=\frac{\sqrt{16}-\sqrt{1}}{16-1}=\frac{4-1}{15}=\frac{3}{15}$ this can be simplified a little more