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anonymous
 4 years ago
Not sure why I forgot but I can't seem to figure out how to find the derivative of this. Can anyone help?
f[x]= C/(x1)....
I know the answer I just need the steps to refresh my memory. thanks
anonymous
 4 years ago
Not sure why I forgot but I can't seem to figure out how to find the derivative of this. Can anyone help? f[x]= C/(x1).... I know the answer I just need the steps to refresh my memory. thanks

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you recall the derivative of 1/x?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0 Factor out constants: =  c (d/dx(1/(x1)))  Use the chain rule, d/dx(1/(x1)) = d/( du)1/u ( du)/( dx), where u = x1 and d/( du)1/u = 1/u^2: =  c ((d/dx(x1))/(x1)^2)  Differentiate the sum term by term: =  (c (d/dx(x)+d/dx(1)))/(x1)^2  The derivative of 1 is zero: =  (c (d/dx(x)+0))/(x1)^2  The derivative of x is 1: =  (c 1 × 1)/(x1)^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0f[x]= C/(x1). = c(x1)^1 f'(x)= c(x1)^2 = c/(x1)^2
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