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anonymous
 4 years ago
Boolean Logic: reduce to a minimum sumofproduct form:
X'Y'Z' + X'YZ + XYZ
X'Y'Z' + X'Y'Z + XY'Z + XYZ'
for the first one, I have it down to X'Y'Z' + YZ, but is there anything more I can do that I'm not seeing?
anonymous
 4 years ago
Boolean Logic: reduce to a minimum sumofproduct form: X'Y'Z' + X'YZ + XYZ X'Y'Z' + X'Y'Z + XY'Z + XYZ' for the first one, I have it down to X'Y'Z' + YZ, but is there anything more I can do that I'm not seeing?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327917442864:dw X'Y'Z' + YZ no other solution for sure ... you are welcome

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02nd one = X'Y'+X(Y'Z+YZ') = X'Y'+Y'Z+YZ' = X'Y' + (Y xor Z)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Chris ... we have not x'y' ... please check your answer . I'm sure its not right answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What do you mean by "we have not x'y'"? The (2nd) given formula was X'Y'Z' + X'Y'Z + XY'Z + XYZ' and there you can easily see, that the first two terms lead to X'Y'(Z'+Z) = X'Y'. Or maybe I misunderstood you?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0look to original Boolean equ X'Y'Z' + X'YZ + XYZ X'Y'Z + XY'Z + XYZ' yours do you have any difference before simplification

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm all the time talking about the 2nd (second, the lower, the latter, the last) of the two expressions that were mentioned in the original post. (At least, as far as I can understand, the two lines with two expressions, one consisting of three, the other of four terms, are two independent expressions, each of he has to reduce.) Maybe I see a different posting, but for me the 2nd expressions reads: \[X'Y'Z' + X'Y'Z + XY'Z + XYZ'\].

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in second term you consider y' while its not ..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0any way .. logic is simple .. and simplification is easy . its just need to take it easy and step by step .. I'm sure that you can solve harder than this, I like your way of deffence because that is mean ... You are completely understand logic ... respect for you buddy .. see u around
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