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- anonymous

The length of the rectangle is 3ft longer than it's width. If it's length is decreased by 3ft. and it's width increased by 2ft, it's area would be decreased by 8 square ft. What is the length of the rectangle?

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- anonymous

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- anonymous

W = (L-3).
(L - 3)(W + 2) + 8 = (L)(W)
But W = (L - 3)
(L - 3)(L -1) + 8 = L(L - 3)
L^2 - 4L +11 = L^2 -3L
L = 11

- anonymous

thankyou

- anonymous

could you explain to me how to do this please

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- anonymous

The length is 3ft longer than width. So width is (L - 3) and length is just (L).
If the length is decreased by 3 (which will now make L - 3) and width is increased by 2 (so (L - 3) + 2), the area of the altered rectangle is now (L - 3) * (L - 3 + 2), which is just (L - 3)(L -1). This rectangle is 8 square feet short of the area of the first rectangle, which is just (L)(L - 3)
Equating them gives the equation (L)(L - 3) = (L -3)(L -1) + 8. Now just solve for L.

- anonymous

I get it

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