A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 4 years ago

Suppose ABC is a right triangle with sides of lengths a, b, and c and right angle at C. Find the unknown side length using the Pythagorean theorem, and then find the values of the six trigonometric functions for angle B. Rationalize denominators when applicable. b = 8, c = 11

  • This Question is Closed
  1. xkehaulanix
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    For clarification, does the problem specify which sides b and c are? The length of the unknown side depends on whether it is a leg of the triangle or not.

  2. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it states that b is 8 and c is 11 and that C is on the right angle of the triangle which means that c is the hypotenuse.

  3. xkehaulanix
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay, so the Pythagorean theorem states that \[a^2+b^2=c^2\] If you rearrange it to find a, it would become \[a=\sqrt[2]{c^2-b^2}\]

  4. xkehaulanix
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm going to guess that your triangle looks something like this, if that was how c was assigned: |dw:1327907085608:dw| The trigonometric functions are sin, cos, tan, csc, sec, and cot.

  5. campbell_st
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    well there are 2 solutions to this a = hypotenuse the a^2 = 8^2 + 11^2 a = shorter side A^2 = 11^2 - 8^2 to you'll need to find 12 ratios...

  6. xkehaulanix
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    If you're going from angle B, then they would look like so: sin(B) = opposite/hypotenuse = b/c cos(B) = adjacent/hypotenuse = a/c tan(B) = opposite/adjacent = b/a sec(B) = hypotenuse/adjacent = c/a csc(B) = hypotenuse/opposite = c/b cot(B) = adjacent/opposite = a/b The sec is a flipped cos, the csc is a flipped sin, and the cot is a flipped tan.

  7. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Still trying to figure what the value of a is. I know you do I turn it to: a^2+b^2=c^2 a^2+8^2=11^2 a^2+64=121 and A^2=54 so that makes it a = \[\sqrt{54}\] However how do I rationalize 54 again? would it be: \[\sqrt{9}*\sqrt{6}\] which would be: \[3\sqrt{6}\] or am I doing it wrong?

  8. xkehaulanix
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You're rationalizing it correctly....but 121-64 doesn't equal 54.

  9. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lol punched it in wrong on my calc. rofl. ok so 57 and I can't rationalize that down any further from what I can tell.

  10. xkehaulanix
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Happens allllll the time, haha. Yep, there's no way to really rationalize it further, so you can move on.

  11. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.