A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
A positive integer is picked randomly from 91 to 100, inclusive.
What is the probability that it is divisible by both 2 and 3?
anonymous
 4 years ago
A positive integer is picked randomly from 91 to 100, inclusive. What is the probability that it is divisible by both 2 and 3?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well for the 3 the set is(93,96,99)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for 2 the set is(92,94,96,98,100)

cristiann
 4 years ago
Best ResponseYou've already chosen the best response.0Divisible by both 2 and 3 mean divisible by 6 (because 2 and 3 are relative prime numbers: their common divisor is 1) So out of 10 numbers you choose 1 number (which is 96) and the probability is 1/10 (the number of favorable cases over the number of all cases)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cool.....if it is by both 2 and 4

cristiann
 4 years ago
Best ResponseYou've already chosen the best response.0Then the above line of reasoning doesn't apply anymore... while a number divisible by 4 is by default also divisible by 2, "both by 2 and 4" means just "by 4"
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.