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pls use the complement approach

That's what I would have thought anyway. What's the probability of not getting heads at all?

ah the probability is getting all tails

Which is?

it is 1/2*1/2*1/2*1/2

1/16

so whts ur reply?

p(of having atlesat one head)=1-p(of having no head)

1-1/16=15/16

there ya go

welll my maths sucks

Hahah well you handled that fine

is there any algorith to solve probability ques

No, they need to be solved on a case-by-case basis.

what is a combinatoral notation?

http://mathworld.wolfram.com/Combination.html
Also,
http://mathworld.wolfram.com/Combinatorics.html

got it u are taking about combination notation of nCr.....

murray what is the other notations for combinations

|dw:1327912574413:dw|

thanx cristann ....is this rule applicable in a pack of cards?