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firstly is it a g.p?

also .. my formula is wrong .. I think it would be somewhat like (2^(n+1) - 1)/(2^(2(2n-2))

no i think your formula worked if you start at n=1

(2^5 -1)/(2^2)^4

got it ... thanks .. yeah my formula is just slightly of.. but thanks anyways.. :)

\(\large \frac 23 \) isn't ?

it cannot be 2/3 because it is (1 + 3/4 + ... ) and all terms are positive

no thats right for the summation part.
multiply by 4 and you get , sum = 8/3

yeah ... it wd be 8/3 ..

thanks both of you.. :)

It wasn't dumcow's I didn't read the thread (fully). My apologies.