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anonymous
 4 years ago
Given that f(x) = x^(2n)  (p+1)x^(2) + p, where n and p are positive integers, show that (x1) is a factor of f(x) for all values of p and... when p=4, find the value of n for which (x+2) is a factor of f(x) and factorise f(x) completely.
anonymous
 4 years ago
Given that f(x) = x^(2n)  (p+1)x^(2) + p, where n and p are positive integers, show that (x1) is a factor of f(x) for all values of p and... when p=4, find the value of n for which (x+2) is a factor of f(x) and factorise f(x) completely.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This might not be the smartest answer but you can show that (x1) is a factor by simply replacing 1 instead of x. This will give you the equation 1(p+1)+p, which is clearly zero, meaning that (x1) is a factor.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah :) thanks, do u know how to find the value of n?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry i cant figure it out. good luck
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