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anonymous

  • 4 years ago

THE EQUATION OF ACURVE IS Y+2X+8/X^2 iii)Show that the normal to the curve at the point (-2,-2) intersects the x- axis at the point (-10,0)

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  1. anonymous
    • 4 years ago
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    sry guys the equation is y=2x+8/x^2

  2. anonymous
    • 4 years ago
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    \[(2x+8)/x^2\] Like this?

  3. anonymous
    • 4 years ago
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    yes

  4. amistre64
    • 4 years ago
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    the normal might be the second derivative if i remember this correctly

  5. amistre64
    • 4 years ago
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    4 (x+12)/x^4 is what the wolf spits out; see if that works for the slope of the line between the 2 points to test

  6. anonymous
    • 4 years ago
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    Wasnt the normal the negative reciprocal of the first derivative?

  7. amistre64
    • 4 years ago
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    -1/4 is the slope between the points: 4(-2+12)/16 = 10/4 = 5/2 bummer yeah, the perp slope lol

  8. amistre64
    • 4 years ago
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    i musta been doing calc3 vectors

  9. anonymous
    • 4 years ago
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    XD

  10. amistre64
    • 4 years ago
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    -(2x+8)/x^3; x=-2 -(-4+8)/-8 = 1/4 so slope is -4 perhaps?

  11. amistre64
    • 4 years ago
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    -10,0 2 , 2 ------- -8,2; slope = -1/4 hmmm

  12. anonymous
    • 4 years ago
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    the slope is -1/4 u good :)

  13. amistre64
    • 4 years ago
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    i cant get the slopes to match up, we sure there aint a typo, in yours or mine?

  14. amistre64
    • 4 years ago
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    other than 1/4 spose to be 1/2 the perps to -2 :)

  15. amistre64
    • 4 years ago
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    2 + 8/x^2 downs to: 0 -16/x^3 at x=-2 we get -16/-8 = 2, perps to -1/2 is locser

  16. amistre64
    • 4 years ago
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    forgot an "x" lol 2x + 8x^-2; 2 - 16x-3; 2 + 2 = 4; which perps tp -1/4 got it lol

  17. anonymous
    • 4 years ago
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    i don`t get it how did we arrive to -1/4?

  18. amistre64
    • 4 years ago
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    which part?

  19. amistre64
    • 4 years ago
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    equation; first derivative = slope at any point; normal is perp slope; perp slope of m = -1/m

  20. anonymous
    • 4 years ago
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    amistre=amazing XD could you explain how you did it to me too :)

  21. amistre64
    • 4 years ago
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    the eq was:\[2x+8x^{-2}\]to begin with

  22. amistre64
    • 4 years ago
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    once you determine the perp sloped derivative :) compare it with the slope of the line between the given points

  23. anonymous
    • 4 years ago
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    thats smart :)

  24. amistre64
    • 4 years ago
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    thnx, and good luck ;)

  25. anonymous
    • 4 years ago
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    thank u next tym :)

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