anonymous
  • anonymous
THE EQUATION OF ACURVE IS Y+2X+8/X^2 iii)Show that the normal to the curve at the point (-2,-2) intersects the x- axis at the point (-10,0)
Mathematics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions.

anonymous
  • anonymous
THE EQUATION OF ACURVE IS Y+2X+8/X^2 iii)Show that the normal to the curve at the point (-2,-2) intersects the x- axis at the point (-10,0)
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
sry guys the equation is y=2x+8/x^2
anonymous
  • anonymous
\[(2x+8)/x^2\] Like this?
anonymous
  • anonymous
yes

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
the normal might be the second derivative if i remember this correctly
amistre64
  • amistre64
4 (x+12)/x^4 is what the wolf spits out; see if that works for the slope of the line between the 2 points to test
anonymous
  • anonymous
Wasnt the normal the negative reciprocal of the first derivative?
amistre64
  • amistre64
-1/4 is the slope between the points: 4(-2+12)/16 = 10/4 = 5/2 bummer yeah, the perp slope lol
amistre64
  • amistre64
i musta been doing calc3 vectors
anonymous
  • anonymous
XD
amistre64
  • amistre64
-(2x+8)/x^3; x=-2 -(-4+8)/-8 = 1/4 so slope is -4 perhaps?
amistre64
  • amistre64
-10,0 2 , 2 ------- -8,2; slope = -1/4 hmmm
anonymous
  • anonymous
the slope is -1/4 u good :)
amistre64
  • amistre64
i cant get the slopes to match up, we sure there aint a typo, in yours or mine?
amistre64
  • amistre64
other than 1/4 spose to be 1/2 the perps to -2 :)
amistre64
  • amistre64
2 + 8/x^2 downs to: 0 -16/x^3 at x=-2 we get -16/-8 = 2, perps to -1/2 is locser
amistre64
  • amistre64
forgot an "x" lol 2x + 8x^-2; 2 - 16x-3; 2 + 2 = 4; which perps tp -1/4 got it lol
anonymous
  • anonymous
i don`t get it how did we arrive to -1/4?
amistre64
  • amistre64
which part?
amistre64
  • amistre64
equation; first derivative = slope at any point; normal is perp slope; perp slope of m = -1/m
anonymous
  • anonymous
amistre=amazing XD could you explain how you did it to me too :)
amistre64
  • amistre64
the eq was:\[2x+8x^{-2}\]to begin with
amistre64
  • amistre64
once you determine the perp sloped derivative :) compare it with the slope of the line between the given points
anonymous
  • anonymous
thats smart :)
amistre64
  • amistre64
thnx, and good luck ;)
anonymous
  • anonymous
thank u next tym :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.