Rotational Motion Problem #2

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Rotational Motion Problem #2

Physics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

One fourth length of a Uniform Rod of mass \(m\) and length \(x\) is placed on rough horizontal surface and it is held stationary by means of a light thread as shown in the figure. The thread is brunt and the rod starts rotating about the edge, the co-efficient of friction of the surface is \(\mu\). Determine the angle between the rod and the horizontal surface at which the rod is about to slip on the edge.
1 Attachment
Help on the FBD (Free Body Diagram) would be great.
Nice problem. It's amazing how something so seemingly simple can be quite so complicated. Call the pivot point A. Notice that if the rod is rotating about A, then there is a force at A. The way to see that is there is a centripetal force from the part to the right/below A; and another centripetal force for the part left/above A. The first of those forces is greater, hence there is a force at A and it points along the direction of the rule. Now, friction must provide that force. The ruler will slip when friction cannot provide the necessary force. So to solve the problem: find an expression for that net centripetal force at A. Find an expression for the maximum frictional force at A. Then find when the former equals (and is about to exceed) the latter.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Thanks!

Not the answer you are looking for?

Search for more explanations.

Ask your own question