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Vt=280mL
m=280g
\[DeltaH=-53.1kJ\]
n=0.12mol
Ti=(Q/mc) -Tf
This is all I got so far.

LiOH+HNO3-------> LiNO3 + H2O+ 53.1kJ

Is that the whole question? It seems a bit vague. :(
How did you get the delta H by the way?

Yeah that is the question.
This equation was given LiOH+HNO3-------> LiNO3 + H2O+ 53.1kJ.

Oh, okay, how about the mass 280 g?

so i calculated the total volume and then i used the density formula to find the total mass.

What you have*

0.00419 kJ/gC*

my teach told me to use deltaHr =deltaH/n

so I first found the n=mv=1.00mol/L * 0.12L=0.12mol

but it is in kJ not kJ/mol :S I'm confused.

Hmm, am I explaining that or just repeating? Don't really know how to say it...

i got -19.1C

The Q should be negative right?

I would guess so, since energy is released. right? then the answer would be -29.9