anonymous
  • anonymous
a neutralization reaction occurs when 120ml of 1.00mol/l lioh and 160nl of 0.75 mol/l hno3 are mixed in an insulated cup. initially, the solutiona are at the same temperature. If the highest temp during mixing was 24.5C, what was the iniyial temp of the solutions? The density is 1.00g/ml and the specific heat capacity is 4.19J/gC.
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Vt=280mL m=280g \[DeltaH=-53.1kJ\] n=0.12mol Ti=(Q/mc) -Tf This is all I got so far.
anonymous
  • anonymous
LiOH+HNO3-------> LiNO3 + H2O+ 53.1kJ
Rogue
  • Rogue
Is that the whole question? It seems a bit vague. :( How did you get the delta H by the way?

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anonymous
  • anonymous
Yeah that is the question. This equation was given LiOH+HNO3-------> LiNO3 + H2O+ 53.1kJ.
Rogue
  • Rogue
Oh, okay, how about the mass 280 g?
anonymous
  • anonymous
so i calculated the total volume and then i used the density formula to find the total mass.
Rogue
  • Rogue
Hmm, I feel like the problem is a bit more complicated than this, but why don't you just try substituting what you?\[T _{i}^{} = \frac {Q}{mc} - T _{f}^{} = \frac {-53 kJ}{280 g * 0.00419 J/gC} - 24.5 C\]
Rogue
  • Rogue
What you have*
Rogue
  • Rogue
0.00419 kJ/gC*
anonymous
  • anonymous
my teach told me to use deltaHr =deltaH/n
anonymous
  • anonymous
so I first found the n=mv=1.00mol/L * 0.12L=0.12mol
Rogue
  • Rogue
Ah, right, 53.0 kJ of energy is released for every 1 mole of LiNO3 formed. So the actual delta H for the sample given would be 53.0 kJ/mol * 0.12 mol = 6.36 kJ
anonymous
  • anonymous
but it is in kJ not kJ/mol :S I'm confused.
Rogue
  • Rogue
Well, according to the reaction, when 1 mole is formed when 53.0 kJ is released. So the delta H rxn = 53.0 kJ/mol.
Rogue
  • Rogue
Hmm, am I explaining that or just repeating? Don't really know how to say it...
anonymous
  • anonymous
Oh okay, now it makes sense :) Thank you soooo much. Let me calculate the final answer and show it to you.
anonymous
  • anonymous
i got -19.1C
Rogue
  • Rogue
The Q should be negative right?
anonymous
  • anonymous
I would guess so, since energy is released. right? then the answer would be -29.9
Rogue
  • Rogue
I really don't like this question :( It'd be great if someone else could also do this question to verify the answer.

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