a neutralization reaction occurs when 120ml of 1.00mol/l lioh and 160nl of 0.75 mol/l hno3 are mixed in an insulated cup. initially, the solutiona are at the same temperature. If the highest temp during mixing was 24.5C, what was the iniyial temp of the solutions? The density is 1.00g/ml and the specific heat capacity is 4.19J/gC.

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Vt=280mL
m=280g
\[DeltaH=-53.1kJ\]
n=0.12mol
Ti=(Q/mc) -Tf
This is all I got so far.

LiOH+HNO3-------> LiNO3 + H2O+ 53.1kJ

Is that the whole question? It seems a bit vague. :(
How did you get the delta H by the way?

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