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anonymous
 4 years ago
?can you spot any errors in my work?
{implicitly differentiate y with respect to x}
y=ln(xy)
dy/dx=[x(dy/dx)+y*1] / [xy]
multiply both sides by (xy)
xy (dy/dx) = x(dy/dx)+y
sutract x(dy/dx) form both sides
xy(dy/dx)x(dy/dx) = y
 factor out dy/dx from the left then divide both sides by (xyx)
dy/dx= y/(xyx)
siplify the right side by facoring out an x
dy/dx=y/x(y1)
anonymous
 4 years ago
?can you spot any errors in my work? {implicitly differentiate y with respect to x} y=ln(xy) dy/dx=[x(dy/dx)+y*1] / [xy] multiply both sides by (xy) xy (dy/dx) = x(dy/dx)+y sutract x(dy/dx) form both sides xy(dy/dx)x(dy/dx) = y  factor out dy/dx from the left then divide both sides by (xyx) dy/dx= y/(xyx) siplify the right side by facoring out an x dy/dx=y/x(y1)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it should be . y/(x (1+y)). which coincidentally is that. so good job :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you for your time :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you for being so polite and awesome :3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0one of the first people i've seen who does their own work =D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well thats the best way to learn

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you for for your time too jimmyrep.
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