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anonymous

  • 4 years ago

The width of a rectangle is 2 less than twice its length. If the area of the rectangle is 83 cm^2, what is the length of the diagonal? Is there a special diagonal formula?

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  1. Mertsj
    • 4 years ago
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    |dw:1327944060314:dw|

  2. Mertsj
    • 4 years ago
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    Let's use x instead of l x(2x-2)=83 2x^2-2x-83=0

  3. anonymous
    • 4 years ago
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    Ok, do i just use the quadratic formula to solve for x?

  4. Mertsj
    • 4 years ago
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    Yes.

  5. anonymous
    • 4 years ago
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    Ok, thank you!

  6. Mertsj
    • 4 years ago
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    yw

  7. anonymous
    • 4 years ago
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    how would i find the length of the diagonal?

  8. Mertsj
    • 4 years ago
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    After you know x you can find the two sides of the rectangle. Those sides are the legs of a right triangle. The diagonal is the hypotenuse so use the Pythagorean Theorem.

  9. anonymous
    • 4 years ago
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    Ok, thanks again!!

  10. Mertsj
    • 4 years ago
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    yw

  11. Mertsj
    • 4 years ago
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    It's not a pretty answer.

  12. anonymous
    • 4 years ago
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    yea, i can't seem to get x when i plug everything into the quad formula i get an imaginary number because of the negative under the radical

  13. Mertsj
    • 4 years ago
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    No.

  14. Mertsj
    • 4 years ago
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    Hang on

  15. anonymous
    • 4 years ago
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    im sorry my arithmetic was incorrect you do get a positive number its radical 668

  16. Mertsj
    • 4 years ago
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    \[x=\frac{2\pm \sqrt{2^{2}-4(2)(-83)}}{2(2)}\]

  17. anonymous
    • 4 years ago
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    thank you that's what i ended up with\[(2\pm \sqrt{668})/4\]

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