A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
does the IVP dy/dt=6y^(2/3), y(1)=0 have a unique solution on an interval containing t=1?
anonymous
 4 years ago
does the IVP dy/dt=6y^(2/3), y(1)=0 have a unique solution on an interval containing t=1?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first step, i have y=(2t+c)^3 is it right?

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.1and now use the initial condition to find c.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that's makes it much easier, thank u

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is y=0 a solution to the IVP? yes isn't it, because when t=1, y=0 or is there another way to determine the solution?

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.1Yes, the zero function is the solution of your ODE. But it's a very uninteresting solution and we don't count it as a solution for the purposes of describing uniqueness.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have another problem: show that y=tant satisfies the IVP y'=1/(1+t^2), y(0)=0. i am confused because the y'(tant) is not 1/(1+t^2). they both do equal 0 with initial condition set to 0 but what do they have to do with each other?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i don't know where to go now because i'm trying to look for the limits of (t,y) to find the largest open interval but tan and arctan limits are not the same, at least for t
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.