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anonymous

  • 4 years ago

HELP PLEASSSSSEEEEEEEEEEEEEEE!!! I put the question in at attachment!!

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  1. anonymous
    • 4 years ago
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  2. radar
    • 4 years ago
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    Using pythg' theorem we come up with the two following equations: \[10^{2}+b ^{2}=(8+a)^{2}\]and\[6^{2}+a ^{2}=b ^{2}\]

  3. radar
    • 4 years ago
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    We can use subsstitution by substituting for b^2 after first expanding the first equation: \[100+b ^{2}= 64+16a+a ^{2}\]\[100 +(36 +a ^{2})=64+16a+a ^{2}\]\[100+36+a ^{2}=64+16a+a ^{2}\]136=64+16a 16a=62 a=62/16=31/8 substitute for a and then solve for b.

  4. anonymous
    • 4 years ago
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    the answer you got for a is not any of my options. My choices are in an attachment below:

  5. anonymous
    • 4 years ago
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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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