anonymous
  • anonymous
prove sigma n^2=n(n+1)(2n+1)/6
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
i know!
anonymous
  • anonymous
that is \[\sum_{1}^{n}\]n^2
anonymous
  • anonymous
then tell?

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anonymous
  • anonymous
NCERT
anonymous
  • anonymous
For reference, you should not use the same variable for the upper limit as you do in the expression. Instead, say \[ \sum_{k=1}^n\space k^2 \]
anonymous
  • anonymous
Do you mean prove it or derive it? It can be proved with induction.
anonymous
  • anonymous
sorry i meant derive it?
anonymous
  • anonymous
http://www.trans4mind.com/personal_development/mathematics/series/sumNaturalSquares.htm In the first proof I don't get this part "...Because \(Δ_3\) is a constant, the sum is a cubic of the form..."

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