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anonymous
 4 years ago
prove sigma n^2=n(n+1)(2n+1)/6
anonymous
 4 years ago
prove sigma n^2=n(n+1)(2n+1)/6

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is \[\sum_{1}^{n}\]n^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For reference, you should not use the same variable for the upper limit as you do in the expression. Instead, say \[ \sum_{k=1}^n\space k^2 \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you mean prove it or derive it? It can be proved with induction.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry i meant derive it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://www.trans4mind.com/personal_development/mathematics/series/sumNaturalSquares.htm In the first proof I don't get this part "...Because \(Δ_3\) is a constant, the sum is a cubic of the form..."
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