At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
Well done for trying. Can you show me your working, either in text, or using Draw, or by scanning/taking a photo and using Attach File?
(-3x^2)^3=-27x^6. (9x^3)^-1=-9x^-3 then i multiplied the two and got 243x^3
Ok, what should the answer be?
oh nvm. what SHOULD it be, lol.
well im thinking i need to get a negative exponent. so that i'll have to put the x in the denominator of a fraction
|dw:1327952013711:dw| Is this what the question is, before we go any further?
Alright, then you got the first bit right, but not the second bit. As you said, negative exponents mean it becomes a denominator.
Do you know this rule?|dw:1327952197252:dw|
yes i do.
so the second part is supposed to be like, -9/x^3
Great, so the second bit becomes |dw:1327952244545:dw|
No, that's where you went wrong
The brackets around the (9x^3) means that all of it goes in the denominator, not just the x^3
In any case, 9^-1 is 1/9, not -9
ok, i just miswrote an example my teacher gave me so that threw me off. i was going by that.
No worries, easy mistake to make :D
What do you make of the final answer then?
i got -3x^3
That seems right to me. Have you got the answers page to check with?
yep its right. thank you for explaining it!
You're most welcome! :)