A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
use the exponent laws to simplify the following until you have only a single power. then evaluate.
anonymous
 4 years ago
use the exponent laws to simplify the following until you have only a single power. then evaluate.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[2^{4} \times(4^{5}\div4^{2}) \over (6 + 7^{3})^{0}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok sarah, first, (4^5)/(4^2)=4^3 4^3=2^4, so we have (2^4)*(2^4) in the denominator, but i can't see the numenator clearly, can u type it again

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont even know what demoninator and numerator mean

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327953048715:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327953037368:dw

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3Here are some laws to know: \[\frac{x^a}{x^b}=x^{ab} ; x^0=1 , x \neq 0\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i know the laws i just dont know how to apply them.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3\[\frac{2^4 \cdot (4^{52})}{1}=2^4 \cdot 4^3\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3and 2^4=2(2)(2)(2)=16 and 4^3=4(4)(4)=64 find the product of 64 and 16 and you will win! :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0apparently im im supost to make the 2 into another number

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ugh!!! this is so confusing! !!!!!

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3Could you tell me where you are having the problem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0where? like the whole problem is a problem i dont know where to start or what to do

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im homeschooled i dont have a teacher to teach me this stuff

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3well right a way i seen the bottom was one since something^0=1 (of course when that something isn't 0)

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3then the two guys inside that parenthesis had the same base and i was like we should apply this law \[\frac{x^a}{x^b}=x^{ab}\] since we had the same base and we are dividing

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3so that is how i got \[\frac{2^4 \cdot (4^{52})}{1}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3since 52=3 and anything over 1 is that anything

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but what happens to the stuff inside the brackets?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and apparently i have to change the 2 so its the same base or sumthin

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3\[2^4 \cdot 4^3\] you don't really need those parathesis anymore

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok i need to simplify.

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3oh you want to write it as 2^something?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont even know what you mean!

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3\[2^{something}\] is that what you are saying what you want?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3i was just going to write 2^4 as 2(2)(2)(2)=16 and 4^3=4(4)(4)=64 and find the product of 16 and 64 since we have \[2^4 \cdot 4^3\] \[16 \cdot 64\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok look at the original question

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im supost to simplify that whole thing

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3so you wanted it as 2^something

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3\[2^4 \cdot (2^2)^3\] since 4 is 2(2)=2^2

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3\[2^4 \cdot 2^6\] since 2(3)=6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont even know what u mean..

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3\[2^{4+6}\] using the law \[x^a \cdot x^b=x^{a+b}\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3i'm sorry can you tell me what is troubling you?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks for your help but i dont understand any math

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i dont understand what to do or anything

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i need like a step by step explination

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3All I'm doing is applying the law of exponents That is what I'm giving you

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3But if you don't understand the step let me know

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3ok so I'm going to write down all the law of exponents we will need: Law 1:\[\frac{x^a}{x^b}=x^{ab}\] Law 2:\[x \neq 0 , x^0=1\] Law 3:\[x^a \cdot x^b=x^{a+b}\] Law 4:\[(x^a)^b=x^{ a \cdot b}\] These are the laws I'm going to use

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3\[2^{4} \times(4^{5}\div4^{2}) \over (6 + 7^{3})^{0} \]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3Ok on the bottom do you see how we can apply law 2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your supost to do brackets first tho

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3It doesn't matter about all that we know the inside is not zero so we can apply law 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so its 1? like for sure?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3That is right ! Great Job! so we have \[2^{4} \times(4^{5}\div4^{2}) \over 1\] By law 2

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3\[2^{4} \times(4^{5}\div4^{2}) \]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3So now this is what is left over

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but u have to change the 2

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3By order of operations we are suppose to look inside the parathesis

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3What law can we apply inside the parathesis?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3We have division and the same base so we can use law 1 is what i called it above

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3\[2^4 \times (4^{52})\] remember this by law 1

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3since 52=3 we can write \[2^4 \times 4^3\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3now since we want the same base we need find out how to write 4 such that it equals 2 to some power \[4=2^2 \] so we can write \[2^4 \times(2^2)^3\]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3i replaced 4 with 2^2 since 4=2^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i get all of it up to thr last bit

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3ok what about 2^4 * 4^3?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3ok let me know if you have a question about that step

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have a question, like whats the next step after it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how do we change the 2 into a 4

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3this is what i wrote \[2^4 \times(2^2)^3 \]

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3\[\text{ remember } 2^2=4\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0whats the mini number

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3you mean the exponent?

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3dw:1327954725191:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so after my last step what do i write lol

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3\[2^4 \times (2^2)^3\] We can rewrite that second part as \[2^{2 \cdot 3}=2^6\] by use of one of the other laws so now we are left with \[2^4 \cdot 2^6\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what does the dot mean

myininaya
 4 years ago
Best ResponseYou've already chosen the best response.3Do you know what to do last?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0k ima draw out what i have and u tell me if its correct ok?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327955081274:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327955246139:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327955289855:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327955357557:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327955389263:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327955419197:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1327955435698:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you so much! omg ! :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.