Use Cramer's rule to solve the system of equations. { 2x+3y=4 x-2y=9

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Use Cramer's rule to solve the system of equations. { 2x+3y=4 x-2y=9

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Are you studying matrices / linear algebra?
yes!
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Other answers:

(If you're stuck from the beginning, that's fine too though!)
i understand how to do it, just the last step is where i mess up. I only know how to put them into the matrix sets, and solve those out. but i have no idea where to go from there.
As I remember it, you create a square matrix A (left hand side of the equation) and column (that's vertical) vector b (right side of the equation). To get x, you replace the first column of your square matrix with vector b, whereas for y you replace the second column of your square matrix with vector b instead. In both cases, you then take the determinant of the new matrix you've created, and divide by the determinant of the original square matrix A. Does that make sense?
If so, we can try it with the numbers now?
If that doesn't make sense, we can do it using Draw.
\[\left[\begin{matrix}2 & 3 \\ 1 & -2\end{matrix}\right]\left(\begin{matrix}x \\ y\end{matrix}\right)=\left(\begin{matrix}4 \\ 9\end{matrix}\right)\]
yea i understand,
Thanks iven5880!
I'm still working on it. I'm not goot at using this editor
So the original square matrix is the one that iven5880 has laid out, and whose determinant is 2*-2 -3*1 = -4-3=-7.
|dw:1327953451141:dw|
Awesome!
arricuhh, does that part make sense to you?
*airricuhh
So x = -35/-7 = 5
yea, i understand (:
Can you do the same thing for y?
can you help me with me it /:
OK, how are you going to start?
|dw:1327953694308:dw|
So y = 14/-7 = 2
oh, welll.. thank you iven5880! and thank you BasketWeave
You're welcome! Mostly thanks to iven5880 though, I'd say :D
:))
You're welcome and thanks BasketWeave
:)

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