anonymous
  • anonymous
What is the equation of the line perpendicular to x+5y=-2 passing through (-3,-4) in standard form?
Mathematics
chestercat
  • chestercat
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hoblos
  • hoblos
slope*(-1/5)=-1 slope=5 y+4=5(x+3) y=5x+11
campbell_st
  • campbell_st
find the gradient of your line.... then the gradient of the perpendicular is -1/m then use point gradient to find the equation..
anonymous
  • anonymous
that is in slope-intercept how do I put y=5x+11 in standard ?

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hoblos
  • hoblos
5x-y=-11
campbell_st
  • campbell_st
so everything on the left hand side.... y - 5x -11 = 0
anonymous
  • anonymous
moving the 11 to the left hand side would make it positive right?
anonymous
  • anonymous
i think I will go with 5x-y=-11, thanks.
hoblos
  • hoblos
yup thats it my pleasure XD

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