## anonymous 4 years ago The density of copper is 10.0 g/mL. What is the volume in milliliters of a 6284-g ingot of copper?

$D = \frac {m}{V}$$10.0 g/mL = \frac {6284 g}{V}$$V = \frac {6284 g}{10.0 g/mL} = 628.4 mL$