Why does X(x+y) - y(x+y)/ x-y factor to (x+y)(x-y)/x-y

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Why does X(x+y) - y(x+y)/ x-y factor to (x+y)(x-y)/x-y

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\[X(x+y) - y(x+y)/x-y = (x+y)(x-y)/x-y\]
where does the x and -y go?
Is X different from x?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

no
factoring out (x+y) in the numerator we get\[\frac{x(x+y)-y(x+y)}{x-y}=\frac{(x+y)(x-y)}{x-y}=x+y\]
but factoring out the x+y 's give you 1
try distributing (x+y) as a whole into (x+y)(x-y)|dw:1327954866293:dw|so it works in reverse as well
|dw:1327954995812:dw|
hmmm
still no?
Ahh see
Kinda like foil
if you backwards foil x(x+y) - y( x+y) you get (x +y) (x-y)
ok let \[a=(x+y)\]so we have\[xa-ya=(x-y)a=(x-y)(x+y)\]
yes factoring is like distributing backwards here it's not really foiling because we don't multiply out the two terms, we treat one as a single variable. Like I said, let\[a=(x+y)\]then it's like distribution\[(x+y)(x-y)=a(x-y)=ax-ay=x(x+y)-y(x+y)\]we just don't multiply it out, and we run in reverse\[x(x+y)-y(x+y)=ax-ay=a(x-y)=(x+y)(x-y)\]
thanks for the help :D
welcome :)

Not the answer you are looking for?

Search for more explanations.

Ask your own question