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anonymous
 4 years ago
Why does
X(x+y)  y(x+y)/ xy
factor to (x+y)(xy)/xy
anonymous
 4 years ago
Why does X(x+y)  y(x+y)/ xy factor to (x+y)(xy)/xy

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[X(x+y)  y(x+y)/xy = (x+y)(xy)/xy\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0where does the x and y go?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2factoring out (x+y) in the numerator we get\[\frac{x(x+y)y(x+y)}{xy}=\frac{(x+y)(xy)}{xy}=x+y\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but factoring out the x+y 's give you 1

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2try distributing (x+y) as a whole into (x+y)(xy)dw:1327954866293:dwso it works in reverse as well

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2dw:1327954995812:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if you backwards foil x(x+y)  y( x+y) you get (x +y) (xy)

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2ok let \[a=(x+y)\]so we have\[xaya=(xy)a=(xy)(x+y)\]

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.2yes factoring is like distributing backwards here it's not really foiling because we don't multiply out the two terms, we treat one as a single variable. Like I said, let\[a=(x+y)\]then it's like distribution\[(x+y)(xy)=a(xy)=axay=x(x+y)y(x+y)\]we just don't multiply it out, and we run in reverse\[x(x+y)y(x+y)=axay=a(xy)=(x+y)(xy)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks for the help :D
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