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anonymous

  • 4 years ago

Perform the operations and simplify. ((7x^3)^4/3)/ (7^1/3x^5)

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  1. xkehaulanix
    • 4 years ago
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    Oh man....this is really hard to read. Is the numerator (7x^3) raised to the 4/3 or raised to the 4th, the whole thing divided by 3? And in the denominator, is 7 raised to the (1/(3x)^5), or is it 7^(1/3) x x^5?

  2. anonymous
    • 4 years ago
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    raised to the 4/3

  3. anonymous
    • 4 years ago
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    on the denominator the 7 is raised to the 1/3. and the x is raised to the 5th

  4. xkehaulanix
    • 4 years ago
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    Cool, that makes things easier. Alright, start with just the numerator: \[(7x^3)^{4/3}\]When you have an exponent raised to an exponent (or things in parenthesis raised by an exponent, in this case 4/3), you can multiply the exponent across all the exponents inside the parenthesis. 7 is raised to the first power (an invisible 1), so multiplying that exponent by 4/3 gives you 7^(1 x 4/3) = 7^(4/3) The x is raised to the third power, so multiplying that one gives you x^(3 x 4/3) = x^4 So the numerator should look like this: \[7^{4/3}x^4\] Moving onto the denominator, there isn't any extra multiplying or simplifying left, so now you can start reducing the entire fraction. Notice that you have a 7 raised to a power in both the numerator and denominator. When you divide like numbers raised to exponents, you subtract the exponent of the denominator (1/3) from the exponent in the numerator (4/3). So the 7s reduce like so: 7^(4/3 - 1/3) 7^(3/3) 7 That's a lot nicer to look at (and type). You repeat the same process with the exponents on the x values. x^(4 - 5) x^(-1) Since your exponent is negative, the x stays in the denominator. Thus the fraction reduces to this: 7/x

  5. anonymous
    • 4 years ago
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    awesome explanation, thank you!

  6. xkehaulanix
    • 4 years ago
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    No problem! Good luck!

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