solve log (base 3) (5x-2)= 4

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solve log (base 3) (5x-2)= 4

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[\log_3 ( 5x -2) = 4\] \[5x -2 = 3^4\] Can u solve now?
the property i used, \[\Large \log_a b = c \to b = a^c\]
how do you get rid of the log base 3 again..

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It's a rule - i dont remember it's name though. i can google if u want. but we change it the i showed in my 2nd comment.
yeah ill look it up.. i just wanna know how to get rid of the log. I just cant remember how.. :/
It's just like this: \[\large \log_a b = c \to b = a^c\]or, \(\log_e 2 = 2\) can be written as \(2= e^2\)
ok

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