anonymous
  • anonymous
An elevator cable breaks when a 920-kg elevator is 28 m above a huge spring (k=22.x 10^5 N/m) at the bottom of the shaft. Calculate the amount the spring compresses (note that work is done by both the spring and gravity.) I already calculated the speed of the elevator just before striking the spring to be 23.4 m/s, and the work done by gravity on the elevator before it hits the spring to be 252, 448 J. How do I find x (spring compression)?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
TuringTest
  • TuringTest
I'm pretty sure that what is necessary here is to notice that just before the elevator hits the spring it has total energy\[K+U=\frac12mv^2+mgx\]where x is the distance the spring will compress. Since all this energy is transferred to the spring we have\[\frac12mv^2+mgx=\frac12kx^2\]which is a quadratic that can be solved for x

Looking for something else?

Not the answer you are looking for? Search for more explanations.