## anonymous 4 years ago Use the quadratic formula to solve x2 + 5x = –2

1. Hero

rewrite it as x^2 +5x + 2 = 0

2. Hero

a = 1 b = 5 c = 2 Plug that into the formula and solve

3. Hero

By the way, the formula is $x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

4. anonymous

$x^2 + 5x = -2$ should be rearranged such the Right Hand Side (RHS) is 0. You can do that by adding 2 to both sides of the equation.

5. anonymous

That would make it $x^2 + 5x + 2 = 0$ the quadratic formular is $(-b \pm \sqrt{b^2 - 4ac})/2a$ a is the coeffecient of x^2 so a = 1 b is the coeffecient of x so b = 5 c is the constant term so c = 2

6. anonymous

So my answer would be -5sqrt17/2?

7. anonymous

$-5\pm \sqrt{17}$

8. anonymous

Where would the 2 go?

9. anonymous

You mean the 2 that was on the RHS ? It would come over to the LHS and become the constant term

10. anonymous

Oh sorry. My mistake. I see what you mean $(-5\pm \sqrt{17})/2$

11. anonymous

I hope I got it right this time :)

12. anonymous

Okay thank you so much :)