Use the quadratic formula to solve x2 + 5x = –2

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Use the quadratic formula to solve x2 + 5x = –2

Mathematics
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rewrite it as x^2 +5x + 2 = 0
a = 1 b = 5 c = 2 Plug that into the formula and solve
By the way, the formula is \[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

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\[x^2 + 5x = -2 \] should be rearranged such the Right Hand Side (RHS) is 0. You can do that by adding 2 to both sides of the equation.
That would make it \[x^2 + 5x + 2 = 0\] the quadratic formular is \[(-b \pm \sqrt{b^2 - 4ac})/2a\] a is the coeffecient of x^2 so a = 1 b is the coeffecient of x so b = 5 c is the constant term so c = 2
So my answer would be -5sqrt17/2?
\[-5\pm \sqrt{17}\]
Where would the 2 go?
You mean the 2 that was on the RHS ? It would come over to the LHS and become the constant term
Oh sorry. My mistake. I see what you mean \[(-5\pm \sqrt{17})/2\]
I hope I got it right this time :)
Okay thank you so much :)

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