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anonymous

  • 4 years ago

Use the quadratic formula to solve x2 + 5x = –2

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  1. Hero
    • 4 years ago
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    rewrite it as x^2 +5x + 2 = 0

  2. Hero
    • 4 years ago
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    a = 1 b = 5 c = 2 Plug that into the formula and solve

  3. Hero
    • 4 years ago
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    By the way, the formula is \[x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

  4. anonymous
    • 4 years ago
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    \[x^2 + 5x = -2 \] should be rearranged such the Right Hand Side (RHS) is 0. You can do that by adding 2 to both sides of the equation.

  5. anonymous
    • 4 years ago
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    That would make it \[x^2 + 5x + 2 = 0\] the quadratic formular is \[(-b \pm \sqrt{b^2 - 4ac})/2a\] a is the coeffecient of x^2 so a = 1 b is the coeffecient of x so b = 5 c is the constant term so c = 2

  6. anonymous
    • 4 years ago
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    So my answer would be -5sqrt17/2?

  7. anonymous
    • 4 years ago
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    \[-5\pm \sqrt{17}\]

  8. anonymous
    • 4 years ago
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    Where would the 2 go?

  9. anonymous
    • 4 years ago
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    You mean the 2 that was on the RHS ? It would come over to the LHS and become the constant term

  10. anonymous
    • 4 years ago
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    Oh sorry. My mistake. I see what you mean \[(-5\pm \sqrt{17})/2\]

  11. anonymous
    • 4 years ago
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    I hope I got it right this time :)

  12. anonymous
    • 4 years ago
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    Okay thank you so much :)

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