• anonymous
Calculus II - Arc Length Just wanted to verify my work and see if anything could be done more easily. Find the exact arc length of the portion of the graph of $y = (1/6)x^3 + 1/(2x)$ from x = 1 to x=2 dy/dx = $(x^2/2) - (1/(2x^2))$ $(dy/dx)^2 = x^4/4 + (1)/(4x^4) - 1/2$ $(dy/dx)^2+1 = x^4/4 + (1)/(4x^4) + 1/2$ $\int\limits_{1}^{2}\sqrt{x^4/4 + 1/(4x^4) + 1/2}$ Arc Length = 17/12
Mathematics
• Stacey Warren - Expert brainly.com
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